\(x+\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+....+\left(x+100\right)=5353\)
\(x+\left(x+x+x+...+x\right)+\left(1+2+3+...+100\right)=5353\)
\(101x+\frac{\left(1+100\right)\times100}{2}=5353\)
\(101x+5050=5353\)
\(101x=5353-5050\)
\(101x=303\)
\(\Rightarrow x=3\)
x + ( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ......... + ( x + 100 ) = 535
101 x + ( 1 + 2 + ... + 100 ) = 535
101x + 5050 = 535
101x = -4515
\(\Rightarrow x=-\frac{4545}{101}\)
x + ( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ......... + ( x + 100 ) = 5353
(x+x+x+x+...+x)+(1+2+3+...+100)=5353
101x + 5050 =5353
101x =5353 - 5050
101x =303
x =303 : 101
x = 3
Vậy ...
x + ( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ......... + ( x + 100 ) = 5353
x + (x+x+x+x+x+…+x)+(1+2+3+…+100) = 5353
101x + 5050 =5353
101x =5353 – 5050
101x =303
x =303 : 101
x =3
x+(x+1)+(x+2)+(x+3)+.....+(x+100)=5353
(x+x+x+x+.....+x)+(1+2+3+....+100)=5353 (có 101 số x)
101x + (1+100)x100:2=5353
101x+5050=5353
101x=303
x=303:101
x=3
câu trả lời là 3 tớ cũng có cách làm giống các bạn trên nhé