\(x.\dfrac{3}{4}=\dfrac{1}{5}.\dfrac{9}{8}\)
\(x.\dfrac{3}{4}=\dfrac{9}{40}\)
\(x=\dfrac{9}{40}:\dfrac{3}{4}\)
\(x=\dfrac{3}{10}\)
Vậy \(x=\dfrac{3}{10}\)
\(x.\dfrac{3}{4}=\dfrac{1}{5}.\dfrac{9}{8}\)
\(x.\dfrac{3}{4}=\dfrac{9}{40}\)
\(x=\dfrac{9}{40}:\dfrac{3}{4}\)
\(x=\dfrac{3}{10}\)
Vậy \(x=\dfrac{3}{10}\)
1 a, 3 va 1/5 - 2 va 1/6 + 1/5
b, 5 va 12/13 - 2 va 15/26 + 1/26
c, 7 va 1/12 + 1/12 - 6 va 1/4
2 tinh gia tri bieu thuc
a, 3 va 2/9 - [1 va 5/8 + 1 va 2/9 ] - 3/8
b, 4 va 2/5 - 1 va 3/7 - 1 va 4/7 + 1/5
c, 1 va 9/12 - 5/4 - 1/2
3 tinh
a, 6 nhan 7 nhan 8 nhan 9 nhan 1 tren 18 nhan 16 nhan 14 nhan 12 nhan 2
b, 4 nhan 15 nhan 9 nhan 24 tren 3 nhan 12 nhan 8 nhan 5
4 rut gon cac phan so
a, 96/150 ; 255/408 ; 630/224
b, 1515/1717; 352352/470470; 200620062006/200520052005
5 so sanh cac phan so
a, 7/9 va 9/7 ; b, 135/120 va 13/8; c, 3535/4848 va 5/8 ; d, 650650/480480 va 222222/144144
6, so sanh hai phan so
a, 2005/2006 va 2006/2007 ; b, 2008/2007 va 2007/2006
cac ban lam tung buoc nha
[X nhan 7 cong 8 ] chia 5 = 10
280 chia [7 cong 3 nhan X] = 4
[ X nhan 5] nhan 19 chia 13= 57
6 nhan [28 - 8] nhan X ] = 72
4 nhan [ 36 - 4 nhan X] = 3,2
[X - 15] nhan 3 chia 12 =6
[ X chia 4 cong 6] nhan 7=70
[ X chia 2 cong 50] chia 5=12
5 nhan [ 7 cong 3 nhan X] = 140
help me ////\\\\\
tim X nha mn jup mk ik mk dg voi lam
x cong x cong x cong1/2 nhan 2/5 nhan x cong 8/10nhan x bang 136 giup minh voi cam on
o 1 nha may co 3 to cong nhan neu lay 20% so cong nhan o to 1 chia deu cho 2 to con lai tyhi so cong nhan o 3 to bang nhau neu to 1 co them 8 cong nhan thi so cong nhan cua to 1 bang tong so cong nhan cua 2 to kia hoi to 1 co ? cong nhan
x nhan 3 nhan 5 bang 2,7
x cong x nhan 2 cong x nhan 3 cong x nhan 4 bang 20,06
Tim x
tich 1 nhan2 nhan 3 nhan 4 nhan ......nhan 99 nhan 100 tan cung bang bao nhieu chu so 0
y nhan 7 cong y nhan 9 tru y tru y nhan 5 bang 790
tinh bang cach thuan tien nhat
7,25 nhan 4,8 nhân 2,25 =...............................
4 nhan 3,75 nhan 2,5=...................
63,4 : 1,25 nhan 5,69 nhan 8..............................