\(\left(x^2+2xy-3\right).\left(-xy\right)=\left[x^2.\left(-xy\right)\right]+\left[3xy.\left(-xy\right)\right]+\left[\left(-3\right).\left(-xy\right)\right]=-x^3y-3x^2y^2+3xy\)
=[x2.(-xy)]+[2xy.(-xy)]+[-3.(-xy)]
=x3y+2x2y2-3xy
\(\left(x^2+2xy-3\right).\left(-xy\right)=\left[x^2.\left(-xy\right)\right]+\left[3xy.\left(-xy\right)\right]+\left[\left(-3\right).\left(-xy\right)\right]=-x^3y-3x^2y^2+3xy\)
=[x2.(-xy)]+[2xy.(-xy)]+[-3.(-xy)]
=x3y+2x2y2-3xy
Rút gọn
(-2x-1)×(x 2-x-3)-(x+2)×(x+1)mũ2
Tìm x
(X+2)×(x-1)-(x-3)×(x+2)=3
x mũ2 +11x-13=0
2x mũ2-5x+2=0
Giúp mk vs mk dg cần gấp
a xy -2x -y^2 +2y
b x^2 - 2xy +y^2 -x +y
c x^2 -1 -2xy +2y
d (x+3)^2 -(2x -5)(x+3)
1.
a.(-xy)(-2x2y+3xy-7x)
b.(1/6x2y2)(-0,3x2y-0,4xy+1)
c.(x+y)(x2+2xy+y2)
d.(x-y)(x2-2xy+y2)
2.
a.(x-y)(x2+xy+y2)
b.(x+y)(x2-xy+y2)
c.(4x-1)(6y+1)-3x(8y+4/3)
(1/3x+2).(3x-6)
(x^2-3x+9).(x+3)
(-2xy+3).(xy-1)
x(xy-1).(xy+1)
(x^2+2xy-3).(-xy-3)
phân tích thành nhân tử
\(a^3 -a^2 x-ay+xy\)
\(x^2 -2xy+x-2y\)
\(x^2 -2x+2y-xy\)
phân tích đa thức thành nhân tử: x^3y - xy^3 - 2xy^2 - xy
3(x-1/3)(9x^2+2xy+y^2)+(x+y)(x^2-xy+y^2)
Phân tích đa thức 3\(x^2\)y + 6\(xy^2\) – 9xy thành nhân tử. Kết quả là:
A. 3(\(x^2y\) + 2\(xy^2\) – 3xy - 3). B. 3y(\(x^2\) + 2xy – 3x). C. xy(3x + 6y - 9). D. 3xy(x + 2y – 3).
X=Y
X^2=XY
X^2+X^2=XY+X^2
2X^2=XY+x^2
2X^2-2XY=XY+X^2+2XY
2(X^2-XY)=1(X^2-XY)
2=1
Đúng hay sai? vì sao?