Tính tổng:
\(K=\frac{2}{1.3.5}+\frac{2}{3.5.7}+...+\frac{2}{99.101.103}\)
tính
B=1.3.5+3.5.7+5.7.9+7.9.11+...+99.101.103
Chứng minh rằng :
B=\(\frac{36}{1.3.5}+\frac{36}{3.5.7}+...+\frac{36}{25.27.29}<3\)
C= \(\frac{1}{4^2}+\frac{1}{6^2}+....+\frac{1}{\left(2n\right)^2}<\frac{1}{4}\left(n\in N;n\ge2\right)\)
Giúp mik nhé
Tính tổng :\(\frac{6}{1.3.5}+\frac{6}{3.7.9}+\frac{6}{7.9.13}+\frac{6}{9.13.15}+\frac{6}{13.15.19}\)
\(\frac{4}{1.3.5}+\frac{4}{3.5.7}+\frac{4}{5.7.9}\)
thu gọn tổng :
\(B=\frac{1}{1.3.5}+\frac{1}{3.5.7}+\frac{1}{5.7.9}+...+\frac{1}{2017.2019.2021}\)
chứng minh rằng
\(B=\frac{36}{1.3.5}+\frac{36}{3.5.7}+\frac{36}{5.7.9}+...+\frac{36}{25.27.29}\)
Chứng minh rằng A = \(\frac{36}{1.3.5}+\frac{36}{3.5.7}+...+\frac{36}{25.27.29}
Tinh hop ly gia tri bieu thuc sau
\(\frac{1}{1.3.5}+\frac{1}{3.5.7}+...+\frac{1}{17.19.21}\)