\(x=\hept{\begin{cases}\frac{1}{2}\\\frac{-1}{2}\end{cases}}\)
Đúng 0
Bình luận (0)
Các câu hỏi tương tự
E=\(\left(\frac{1}{x^2+4x+4}-\frac{1}{x^2-4x+4}\right):\left(\frac{1}{x+2}+\frac{1}{x-2}\right)\)
F=\(\frac{1}{x-1}-\frac{x^3-x}{x^2+1}\left(\frac{1}{x^2-2x+1}+\frac{1}{1-x^2}\right)\)
B=\(\frac{3x+1}{x^2-2x+1}-\frac{1x}{x+1}+\frac{x+3}{1-x^2}\)
C=\(\left(\frac{x}{x+1}+1\right):\left(1-\frac{3x^2}{1-x^2}\right)\)
D=\(\left(\frac{x^2}{y^2}+\frac{y}{x}\right):\left(\frac{x}{y^2}-\frac{1}{y}+\frac{1}{x}\right)\)
1. So sánh:a. 1 và frac{1}{2}+frac{1}{2^2}+frac{1}{2^3}+.....+frac{1}{2^{50}}b. frac{1}{3}+frac{1}{3^2}+frac{1}{3^3}+.....+frac{1}{3^{100}}với frac{1}{2}c. frac{1}{4}+frac{1}{4^2}+frac{1}{4^6}+.....frac{1}{4^{1000}}với frac{1}{3}2. Tìm x, biết:a.left(frac{2}{5}-xright):1frac{1}{3}+frac{1}{2}-4b.3-frac{1-frac{1}{2}}{1+frac{1}{x}}2frac{2}{3}c.4^x+4^{x+3}4160d.2^{x-1}+5.2^{x-2}frac{7}{32}e.frac{x-100}{24}+frac{x-98}{26}+frac{x-96}{24}3g.frac{x-1}{65}+frac{x-3}{63}+frac{x-5}{61}+frac{x-7}{59}
Đọc tiếp
1. So sánh:
a. 1 và \(\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+.....+\frac{1}{2^{50}}\)
b. \(\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+.....+\frac{1}{3^{100}}\)với \(\frac{1}{2}\)
c. \(\frac{1}{4}+\frac{1}{4^2}+\frac{1}{4^6}+.....\frac{1}{4^{1000}}\)với \(\frac{1}{3}\)
2. Tìm x, biết:
a.\(\left(\frac{2}{5}-x\right):1\frac{1}{3}+\frac{1}{2}=-4\)
b.\(3-\frac{1-\frac{1}{2}}{1+\frac{1}{x}}=2\frac{2}{3}\)
c.\(4^x+4^{x+3}=4160\)
d.\(2^{x-1}+5.2^{x-2}=\frac{7}{32}\)
e.\(\frac{x-100}{24}+\frac{x-98}{26}+\frac{x-96}{24}=3\)
g.\(\frac{x-1}{65}+\frac{x-3}{63}+=\frac{x-5}{61}+\frac{x-7}{59}\)
Tìm x,y biết : |x-y|1frac{1}{2}a)frac{-1}{2}+left(x-3right):frac{-1}{2}-1frac{2}{3}c)left(frac{1}{3}-xright)^2frac{1}{4} b)2,25+frac{3}{2}:left(x-5right)2frac{1}{2}d)frac{3}{2}+frac{x-1}{3}1e)frac{-6}{8}+frac{x}{12}frac{5}{6}g)frac{1}{2}-frac{1}{3}left(x-2right)frac{-2}{3}h)frac{5}{2}left(x+1right)-frac{1}{2}3frac{1}{2}k)frac{x}{3}-frac{1}{2}-2left(x+1right)+3
Đọc tiếp
Tìm x,y biết : |x-y|=1\(\frac{1}{2}\)
a)\(\frac{-1}{2}+\left(x-3\right):\frac{-1}{2}=-1\frac{2}{3}\)
c)\(\left(\frac{1}{3}-x\right)^2=\frac{1}{4}\)
b)\(2,25+\frac{3}{2}:\left(x-5\right)=2\frac{1}{2}\)
d)\(\frac{3}{2}+\frac{x-1}{3}=1\)
e)\(\frac{-6}{8}+\frac{x}{12}=\frac{5}{6}\)
g)\(\frac{1}{2}-\frac{1}{3}\left(x-2\right)=\frac{-2}{3}\)
h)\(\frac{5}{2}\left(x+1\right)-\frac{1}{2}=3\frac{1}{2}\)
k)\(\frac{x}{3}-\frac{1}{2}=-2\left(x+1\right)+3\)
Tìm x biết:
1) \(\frac{x+1}{2}+\frac{x+1}{3}+\frac{x+1}{4}=\frac{x+1}{5}+\frac{x+1}{6}\)
2) \(\frac{x+1}{2009}+\frac{x+2}{2008}+\frac{x+3}{2007}=\frac{x+10}{2000}+\frac{x+11}{1999}+\frac{x+12}{1998}\)
tim xa)2frac{3}{4}x-1frac{5}{8}x1b)2frac{3}{4}x-1frac{5}{8}x1c)frac{3}{2}x-frac{2}{5}frac{1}{3}x-frac{1}{4}d)2x-frac{1}{4}frac{5}{6}-frac{1}{2}xe)frac{-5}{6}+3xfrac{2}{3}-frac{1}{2}xf)frac{5}{2}x-frac{3}{2}x+frac{29}{10}g)frac{2}{3}+frac{7}{3}xfrac{5}{4}x+frac{1}{6}h)frac{1}{3}.x+frac{2}{5}left(x-1right)0giup mk nha moi nguoi
Đọc tiếp
tim x
a)\(2\frac{3}{4}x-1\frac{5}{8}x=1\)
b)\(2\frac{3}{4}x-1\frac{5}{8}x=1\)
c)\(\frac{3}{2}x-\frac{2}{5}=\frac{1}{3}x-\frac{1}{4}\)
d)\(2x-\frac{1}{4}=\frac{5}{6}-\frac{1}{2}x\)
e)\(\frac{-5}{6}+3x=\frac{2}{3}-\frac{1}{2}x\)
f)\(\frac{5}{2}x-\frac{3}{2}=x+\frac{29}{10}\)
g)\(\frac{2}{3}+\frac{7}{3}x=\frac{5}{4}x+\frac{1}{6}\)
h)\(\frac{1}{3}.x+\frac{2}{5}\left(x-1\right)=0\)
giup mk nha moi nguoi
Tìm số hữu tỉ x,biết:
a, \(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}+\frac{x+1}{15}\)
b, \(\frac{x+4}{2012}+\frac{x+3}{2013}+\frac{x+2}{2014}=\frac{x+1}{2015}+\frac{x-1}{2016}+\frac{x-2}{2017}\)
c, ( x - 2 )( x + 4 ) = 0
d, ( x + 1 )( x - 2 ) < 0
e, ( x - 2 )( x + \(\frac{1}{2}\)) > 0
giúp mình mới
CMR: \(\frac{1}{2^2}-\frac{1}{2^4}+\frac{1}{2^6}-...+\frac{1}{2^{2002}}-\frac{1}{2^{2004}}< 0,2\)
tìm x biết:
\(|x-\frac{1}{3}|=|\left(-3,2\right)+\frac{2}{5}|\)
\(\frac{x-1}{2011}+\frac{x-2}{2010}-\frac{x-3}{2009}=\frac{x-4}{2008}\)
Tìm x biết
a) (8-5x).(x+2)+4.(x-2).(x+1)+2.(x-2).(x+2)=0
b)\(\left(-\frac{2}{5}+x\right):\frac{7}{9}+\left(-\frac{3}{5}+\frac{5}{6}\right):\frac{7}{9}=0\)
c)\(1+\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{2}{x\left(x+1\right)}=1\frac{2003}{2004}\)
\(\frac{1}{2}x+2\frac{1}{2}=3\frac{1}{2}x-\frac{3}{4}\)
\(\frac{1}{3}x+\frac{2}{5}\left\{x+1\right\}=0\)
\(\frac{2}{3}-\frac{1}{3}\left\{x-\frac{3}{2}\right\}-\frac{1}{2}\left\{2x+1\right\}=5\)