Question

( x + \(\frac{1}{2}\) ) * ( \(\frac{2}{3}\) * 2  ) * x =0

giúp mk nha ai nhanhh mk tk cho

 

Answer 1

Từ đề bài => 2 trường hợp

th1: x=0

th2: x=\(\frac{-1}{2}\)

Answer 2

\(\left(x+\frac{1}{2}\right)\times\left(\frac{2}{3}\times2\right)\times x=0\)

\(\left(x+\frac{1}{2}\right)\times\frac{4}{3}\times x=0\)

\(\Rightarrow x+\frac{1}{2}=0\) HOẶC \(x=0\)

             \(x=0-\frac{1}{2}=-\frac{1}{2}\)

       VẬY, \(x=-\frac{1}{2}\) HOẶC \(x=0\)

Answer 3

\(\left(x+\frac{1}{2}\right)\cdot\left(\frac{2}{3}\cdot2\right)\cdot x=0\)

\(\left(x+\frac{1}{2}\right)\cdot\frac{4}{3}x=0\)

\(\Rightarrow\hept{\begin{cases}x+\frac{1}{2}=0\\\frac{4}{3}x=0\end{cases}}\)

\(1.x+\frac{1}{2}=0\)

\(\Rightarrow x=-\frac{1}{2}\)

\(2.\frac{4}{3}x=0\)

\(x=0\)

Vậy \(x\in\left\{-\frac{1}{2};0\right\}\)