Question

(x + \(\frac{1}{2}\) ) : \(\frac{1}{1+\frac{1}{2}}\) = \(\frac{1}{1+\frac{1}{2}}\)

Answer 1

\(\left(x+\frac{1}{2}\right):\frac{1}{1+\frac{1}{2}}=\frac{1}{1+\frac{1}{2}}\)

\(\left(x+\frac{1}{2}\right):\frac{1}{\frac{3}{2}}=\frac{1}{\frac{3}{2}}\)

\(x+\frac{1}{2}=\frac{2}{3}.\frac{2}{3}=\frac{4}{9}\)

\(x=\frac{4}{9}-\frac{1}{2}=-\frac{1}{18}\)

Answer 2

\(\left(x+\frac{1}{2}\right):\frac{2}{3}=\frac{2}{3}\)

\(x+\frac{1}{2}=\frac{2}{3}.\frac{2}{3}\)

\(x+\frac{1}{2}=\frac{4}{9}\)

\(x==\frac{4}{9}-\frac{1}{2}\)

\(x=\frac{4}{9}-\frac{1}{2}\)

\(x=\frac{1}{18}\)