Question

x + \(\dfrac{1}{3}\)=\(\dfrac{7}{26}.\dfrac{-13}{6}\)

Answer 1

\(x+\dfrac{1}{3}=-\dfrac{7}{12}\\ \Rightarrow x=-\dfrac{7}{12}-\dfrac{1}{3}=-\dfrac{7}{12}-\dfrac{4}{12}=-\dfrac{11}{12}\)

Answer 2

\(x+\dfrac{1}{3}=\dfrac{7}{26}.\dfrac{-13}{6}\)

\(x+\dfrac{1}{3}=\dfrac{-91}{156}\)

\(x+\dfrac{1}{3}=\dfrac{-7}{13}\)

\(x=\dfrac{-11}{12}\)

Answer 3

\(x+\dfrac{1}{3}=\dfrac{7}{26}.\dfrac{-13}{6}\)=>\(x+\dfrac{1}{3}=\dfrac{-7}{12}\)=>\(x=\dfrac{-7}{12}-\dfrac{1}{3}=\dfrac{-11}{12}\)

Answer 4

Answer 5

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