x = 15-x = 15 / 5 = 1\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)=?
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)