\(\left(x-890\right)\times\left(74-x\right)=0\)
\(\hept{\begin{cases}x-890=0\\74-x=0\end{cases}\Leftrightarrow\hept{\begin{cases}x=0+890\\x=74-0\end{cases}\Leftrightarrow}\hept{\begin{cases}x=890\\74\end{cases}}}\)
Vậy \(x=890;x=74\)
Vì (x-890)×(74-x)=0
nên x-890=0 ;
74-x=0
Vậy x=890 ; x=74.