Question

x + 8 ⋮ x + 3

Answer 1

Bổ sung đề : Tìm `x\in ZZ`

`ĐK:x\ne -3`

`x+8\vdots (x+3)`

`=>(x+3)+5\vdots (x+3)`

`=>5\vdots (x+3)`

`=>x+3\in Ư(5)={+-1;+-5}`

`=>x\in {-4;-2;-8;2}\  (TMDK)`

 

Answer 2

\(x+8⋮x+3\)
\(\Rightarrow x+3+5⋮x+3\)
\(Mà\) \(x+3⋮x+3\Rightarrow5⋮x+3\)
\(\Rightarrow x+3\inƯ\left(5\right)=\left\{1;5\right\}\)
\(\Rightarrow x\in\left\{-2;2\right\}\)

Answer 3

??????????????????