x : 7 = 6 (dư 5)
x = 6 x 7 + 5
x = 42 + 5
x = 47.
x : 7 = 6 (dư 5)
=> (x-5) : 7 =6
x =6 x 7 + 5
x =47
vậy x = 47
x : 7 = 6 (dư 5)
x = 6 * 7 + 5
x = 42 + 5
x = 47
x : 7 = 6 ( dư 5 )
x = 6 x 7 + 5
x = 47
\(x\div7=6\)\(dư\)\(5\)
\(x\) \(=\)\(6\times7+5\)
\(x\) \(=47\)
x : 7 = 6 ( dư 5 )
x = 6 * 7
x = 42
x = 42 + 5
x = 47