(x-5)x[1 - (x-5)] =0 =>
(x-5)x(4-x ) =0
=> x -5 =0 hay x =5
hoặc 4 -x =0 hay x =4
Vậy x =4 ;x=5
Đúng 0
Bình luận (0)
Các câu hỏi tương tự
|x-3| + |y-2x | =0 |x| + 3|2x -x ² | =0 |5x ² -5 | + 4|y-7 | =0 ||x +1 | + |y-5 |=0 |x ² -1| + |y-1| =0 |x-1 | +|x ²-x |=0
a) 5/2 - x + 4/5 = 2/3 + 4/7
b) ( x - 1 ) x ( x + 2 )< 0
c) ( x + 3/5 ) x ( x+ 1 )<0
d) ( x - 1/3 ) x ( x + 2/5 )>0
a,x.(4/5.x-1),(0,1.x-10)=0 b,(1/4.x-1)-(5/6.x+2)-(1-5/8.x)=0
Tìm x,y nguyên:
1) (2x-1).(2x-5)<0
2) (3x+1).(5-2x)>0
3) (3-2x).(x+2)>0
4) (2-x).(x+1)=|y+1|
5) (x+3).(1-x)=|y|
6) (x-2).(5-x)=|2y+1|+2
7)(x-3).(x-5)+|y-2|=0
8) (x-2).(5-x)-|y+1|=1
GIÚP MK VS MK TICK CHO
THANK FOR WATCHING!
a) (- 7) . ( 5 – x) 0
b) 11 ⁝ x – 1
c) x + 8 ⁝ x + 1
d) (x + 2) . (5 – x) 0
Đọc tiếp
a) (- 7) . ( 5 – x) < 0
b) 11 ⁝ x – 1
c) x + 8 ⁝ x + 1
d) (x + 2) . (5 – x) > 0
tìm x
(x-1).(x+3)<0
(2-1).(x+5) >0
(x-5).(x+1/2)>0
(x+1).(x-3/2)<0
Bt1 tìm x
a) (3/x+1/5).(x-1/2)=0
b)(x-3/2).(2x+1)>0
c)(x-2).(x-4)<0
d)(3x+1/5).(2x-1)<0
e)(x-1).(3x-5)<0
Bài 1: tìm x
c) | x | 3,5
d) | x | -2,7
e) | 1 - x | + 0,73 3
f) 52 . 73 . 11x + 52 . 72 .11 0
g) (3 . 5 + 5 . 7)x + ( 3 . 5 + 5 . 7) + (3 . 5 + 5 . 7) 0
h) 52 . 72 . 112x - 52 . 72 . 114 0
l) | x + dfrac{3}{4} | - 5 -2
Đọc tiếp
Bài 1: tìm x
c) \(|\) x \(|\) = 3,5
d) \(|\) x \(|\) = -2,7
e) \(|\) 1 - x \(|\) + 0,73 = 3
f) 52 . 73 . 11x + 52 . 72 .11 = 0
g) (3 . 5 + 5 . 7)x + ( 3 . 5 + 5 . 7) + (3 . 5 + 5 . 7) = 0
h) 52 . 72 . 112x - 52 . 72 . 114 = 0
l) \(|\) x + \(\dfrac{3}{4}\) \(|\) - 5 = -2
Bài 1: Tìm x:
a) (x-1) . (x+2) > 0
b) (x-1/3) . (x+2/5) > 0
c) (x+3/5) . (-x) < 0
tìm x biết
a) (5x-1)(2x-1/3)=0
b) (x^2+1)(x-4)=0
c) 2x^2 -1/3x=0
d) (4/5)^5.x=(4/5)^7
e)Tìm x thuộc z để A=x+5/x-2 có giá trị nguyên