\(x-5+x-5+x-5=15\)
\(\left(x-5\right)\times3=15\)
\(x-5=15\div3\)
\(x-5=5\)
\(x=5+5\)
\(x=10\)
Ta có: x-5+x-5+x-5=15
=>(x-5).3=15
=>x-5=15:3
=>x-5=5
=>x=5+5
=>x=10
Ta có: x-5+x-5+x-5=15
=>(x-5).3=15
=>x-5=15:3
=>x-5=5
=>x=5+5
=>x=10
X x 3 - (5x3)=15 X x 3 - 15 =15 X x 3= 15+15 X x 3 =30 X=30:3=10
x-5+5+5=15
x-5+5 =15-5=10
x-5 =10-5=5
x=5+5
x=10
cach lay de hieu hon em a