Có \(\left(x-5\right)^2=\left(1-3x\right)^2\)\(\Leftrightarrow x-5=1-3x\)\(\Leftrightarrow x+3x=1+5\)\(\Leftrightarrow4x=6\)\(\Leftrightarrow x=6:4\)\(\Leftrightarrow x=\frac{3}{2}\)Câu trả lời: Có \(\left(x-5\right)^2=\left(1-3x\right)^2\)\(\Leftrightarrow x-5=1-3x\)\(\Leftrightarrow x+3x=1+5\)\(\Leftrightarrow4x=6\)\(\Leftrightarrow x=6:4\)\(\Leftrightarrow x=\frac{3}{2}\)