(x - 5)2 = 64
=> (x - 5)2 = 82 = (-8)2
=> \(x-5\in\left\{8;-8\right\}\)
=> \(x\in\left\{13;-3\right\}\)
( x - 5 )2 = 64
\(\Leftrightarrow\)(x - 5)2 = 82
\(\Rightarrow\)x - 5 = 8
\(\Rightarrow\)x = 8 - 5
\(\Rightarrow\)x = 3
(x-5)2=64
=>(x-5)2=82hoặc (x-5)2=(-8)2
=> x=13 hoặc x=-3
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(x-5)2 = 64
(x-5) = \(\sqrt{64}\)
(x-5) = 8
x = 8+5
vậy x = 13
\(\left(x-5\right)^2=64\)
\(\Leftrightarrow\hept{\begin{cases}\left(x-5\right)^2=8^2\\\left(x-5\right)^2=-8^2\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}x-5=8\\x-5=-8\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}x=8+5\\x=-8+5\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}x=13\\x=-3\end{cases}}\)
Vậy \(x\in\left\{13,-3\right\}\)
\(\left(x-5\right)^2=64\)
\(\left(x-5\right)^2=8^2\)
\(\Rightarrow x-5=8\)
\(\Rightarrow x=8+5\)
\(\Rightarrow x=13\)
