\(x+567+x-67=x+90\\ \Rightarrow\left(x+x\right)+\left(567-67\right)=x+90\\ \Rightarrow2x+500-x-90=0\\ \Rightarrow x+410=0\\ \Rightarrow x=-410\)
`x+567 +x-67=x+90`
`=>(x+x)+(567-67)=x+90`
`=>2x+500=x+90`
`=>2x-x=90-500`
`=>x= - 410`
Vậy `x=-410`
x+567+x-67=x+90
x+(567-67)=x+90
2x+500-x-90=0
x+410=0
x=-410