(x - 5)4 = (x - 5)6
=> (x - 5)4 [1 - (x - 5)2] = 0
=> (x - 5)4 (1 - x2 + 10x - 25) = 0
=> (x - 5)4 (-x2 + 10x - 24) = 0
=> (x - 5)4 (x - 6)(x - 4) = 0
=> x - 4 = 0 => x = 4
hoặc (x - 5)4 = 0 => x - 5 = 0 => x = 5
hoặc x - 6 = 0 => x = 6
Vậy x = {4;5;6}