(x - 5)2 = (1 - 3x)2
=> x - 5 = 1 - 3x
=> 4x = 6
=> x = 1,5
\(\left(x-5\right)^2=\left(1-3x\right)^2\)
\(\Rightarrow x-5=1-3x\)
\(\Rightarrow x+3x=1+5\)
\(\Rightarrow4x=6\)
\(\Rightarrow x=6:4\)
\(\Rightarrow x=1,5\)
Vậy x = 1,,5
Theo đầu bài ta có:
\(\left(x-5\right)^2=\left(1-3x\right)^2\)
TH1: \(\Rightarrow x-5=1-3x\)
\(\Rightarrow x+3x=1+5\)
\(\Rightarrow4x=6\)
\(\Rightarrow x=1,5\)
TH2: \(\Rightarrow x-5=-\left(1-3x\right)\)
\(\Rightarrow x-5=3x-1\)
\(\Rightarrow3x-x=1-5\)
\(\Rightarrow2x=-4\)
\(\Rightarrow x=-2\)