\(\left(x-4\right)^2=\left(2x+1\right)^2\)
\(\Leftrightarrow\left(x-4\right)^2-\left(2x+1\right)^2=0\)
\(\Leftrightarrow\left(x-4-2x-1\right)\left(x-4+2x+1\right)=0\)
\(\Leftrightarrow\left(x-5\right)\left(3x-3\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-5=0\\3x-3=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=5\\3\left(x-1\right)=0\end{cases}}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=5\\x-1=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=5\\x=1\end{cases}}}\)
(x-4)2 = (2x+1)2
=> x-4 = 2x +1
x - 2x = 1 +4
-x = 5
x=-5
<=> x-4=2x=1
<=> x-2x=1+4
<=> -x =5
<=> x=-5
Vì (x - 4)2 = (2x + 1)2
=> x - 4 = 2x - 1
=> x - 2x = -1 + 4
=> -x = 3
=> x = - 3
Vậy x = -3
Ủng hộ mk nha !!! ^_^
(x-4)2=(2x+1)2
x-4=2x+1
x=2x+5
0=x+5
x=-5
(x-4)^2=(2x+1)^2
=>x-4=2x+1
x-2x=4+1
-x=5
=>x=-5