Question

 

 

(x-3)(x^2+3x+9)-(3x-17)=x^3-12

Answer 1

223" role="presentation" style="border:0px; box-sizing:border-box; direction:ltr; display:inline; float:none; line-height:normal; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; padding:0px; position:relative; white-space:nowrap; word-spacing:normal; word-wrap:normal" class="MathJax">⇒3x=22⇒x=223

Answer 2

(x−3)(x^2+3x+9)−(3x−17)=x^3−12

⇔x^3−27−3x+17=x^3−12

⇔−10−3x=−12

⇔3x=2

⇔x=2/3

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