(x - 3) . (x - 4) > 0
=> 1 trong 2 thừa số phải bé hơn 0
=> có 2 th
\(1\hept{\begin{cases}x-3< 0\\x-4>0\end{cases}\Rightarrow\hept{\begin{cases}x< 3\\x>4\end{cases}\Rightarrow4< x< 3\Rightarrow}x=O}\)
\(2\hept{\begin{cases}x-3>0\\x-4< 0\end{cases}\Rightarrow\hept{\begin{cases}x>3\\x< 4\end{cases}\Rightarrow}3< x< 4}\)
Tìm x: a)x*x+2*x-3=0 c)x*x+x+1=0 e)x*x-4*x+4=0
b)2*x*x+3*x+1=0 d)x*x-x-6=0
Tìm X:
a) (X - 1) (X+3)<0
b) (X - 2) (X - 4) (X+5)>0
c) (X2 - 4) (X - 3)<0
d) (X2 - 9) (X+4)>0
Tìm X:
a) (X - 1) (X+3)<0
b) (X - 2) (X - 4) (X+5)>0
c) (X2 - 4) (X - 3)<0
d) (X2 - 9) (X+4)>0
|x-3| + |y-2x | =0 |x| + 3|2x -x ² | =0 |5x ² -5 | + 4|y-7 | =0 ||x +1 | + |y-5 |=0 |x ² -1| + |y-1| =0 |x-1 | +|x ²-x |=0
2(x+1)-4x=6
3(2-x)+4(5-x)=4
7/3(x-4/3)+2/5(4-1/3x)=0
(x+1)(x-3) =0
nhanh giúp mik nha
giúp mik bài này với
a) |x - 2| + |y + 3| = 0
b) |x - 2| - |x + 3| = 0
c) |x - 3/4| + |x + 5/4| = 1a) 5/2 - x + 4/5 = 2/3 + 4/7
b) ( x - 1 ) x ( x + 2 )< 0
c) ( x + 3/5 ) x ( x+ 1 )<0
d) ( x - 1/3 ) x ( x + 2/5 )>0
Bài 1: Tìm x biết
1) |5x - 3| = |7 - x|
2) 2 |3 x - 1| - 3x = 7
3) |2x + 3| + 4 = -2x
4) |x + 3/4| - 1/3 = 0
5) 1,6 - |x + 1,5| = 0
6) |x - 1,5| + |2,5 - x| = 0
1) x2019 - 1 = 0
2) x4 - 16 = 0
3) 32 - x5 = 0
4) ( x - 2 )3 = ( 1 - 3x )3
5) ( 4 - 3x )10 - ( 3 + x ) = 0
6) x2 = x
7) x6 = x3
8) ( x - 3 )5 = 4 ( x - 3 )
Tìm x biết
( x+1 ).( x-2 ) >0 ;
( x-2 ).( x-3 ) >0 ;
x ( x-4 ) >0 ;
x ( x-4 ) <0
