\(\left(x+35\right)+\left(x+65\right)=200\)
\(x+35+x+65=200\)
\(2x+100=200\)
\(2x=200-100\)
\(2x=100\)
\(x=100:2\)
\(x=50\)
(\(x\) + 35) + (\(x\) + 65) = 200
\(x\) + 35 + \(x\) + 65 = 200
(\(x\) + \(x\)) + ( 35 + 65) = 200
2\(x\) + 100 = 200
2\(x\) = 200 - 100
2\(x\) = 100
\(x\) = 100 : 2
\(x\) = 50
Vậy \(x\) = 50
(x + 35) + (x + 65) = 200
x + 35 + x + 65 = 200
2x + (35 + 65) = 200
2x + 100 = 200
2x = 200-100
2x= 100
x= 50
( + 35) + ( + 65) = 200
+ 35 + + 65 = 200
( + ) + ( 35 + 65) = 200
2 + 100 = 200
2 = 200 - 100
2 = 100
= 100 : 2
= 50
Vậy = 50