Tim x, y, z biet
a ) |x-3,5|+ |x+5|=0
b) |x-1| + (y+1)^2 + |z-1|=0
c) ( x-1/3)^2 + (y-2)^2+ (z-1)^2 be hon hoac bang 0
d)(x-z)^2+ (y+x)^2 + (z+1/4)^2 =0
Cac ban giup minh voi minh can gap lam
cho |2x-1|+(3y+2)2 be hon hoac bang 0
tinh S=x2+y2-xy
\(\left|x-2016\right|^{2015}+\left|y+2015\right|^{2016}\) be hon hoac bang 0
cho ham so y= f(x) =6/x
tinh f(1) ; f(1.5) ;f(2) ;f(3) ;f(-2/3)
tim x biet y=3 ; y=-2
tim y biet 1<x>3 ; 1.5 be hon hoac bang x lon hon hoac bang 6
diem nao trong cac diem sau day khong thuoc do thi ham s
A(-1;-6 ) ; B(-0.5 ;-12 ) ;C(-0.5 ; -13 ) ; D(-1/3 ; -3 )
cho f(x)=a(x^2)+bx+c voi a,b,c la cac so huu ti.chung minh f(-2).f(3) be hon hoac bang 0.biet rang 13a+b+2c=0
chung minh rang : -3x^2+6x-y^2+6y-12 nho hon hoac bang 0
(cac ban giai nhanh nhe 5 like , minh dang can gap)
cho ba so a,b,c thoa man 0be honhoac bang a be hon hoac bang b+1 be hon hoac bang c+2 va a+b+c=1 tim gia tri nho nhat cua c
cau 1 ,cho m,n thuoc n va p la so nguyen to thoa man p/m-1=m+n/p
CMRp^2=n+2
cau 2,cho a,b,c thoa man a+b+c=0 CMRab+bc+ca be hon hoac bang 0
cau 3,bay gio la 4 gio 10 phut hoi sau it nhat bao lau thi hai kim dong ho nam doi dien nhau tren mot duong thang
cau 4,so 2^100 viet trong he thap phan tao thanh 1 so hoi so do co bao nhieu chu so
cau 5,cho a,b,c la so do 3 canh cua mot tam giac vuong voi c la so do canh huyen CMRa^2n+b^2n be hon hoac bang c^2n (n la so tu nhien lon hon 0 )
cho ham so \(y=f\left(x\right)=ax^2+bx+c\)(a;b;c thuoc Q)
chung to rang f(-2)*f(3) nho hon hoac bang 0, biet rang 13a+b+2c=0