\(\left(x-\frac{3}{4}\right)^6=\frac{9}{4}.\left(x-\frac{3}{4}\right)^4\)
\(\frac{\left(x-\frac{3}{4}\right)^6}{\left(x-\frac{3}{4}\right)^4}=\frac{9}{4}\)
\(\left(x-\frac{3}{4}\right)^2=\left(\frac{3}{2}\right)^2\)
\(\Rightarrow\orbr{\begin{cases}x-\frac{3}{4}=\frac{3}{2}\\x-\frac{3}{4}=-\frac{3}{2}\end{cases}\Leftrightarrow\orbr{\begin{cases}x=\frac{9}{4}\\x=-\frac{3}{4}\end{cases}}}\)
Vậy \(x=\frac{9}{4}\)hoặc \(x=-\frac{3}{4}\)
Tham khảo nhé~
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