(x-3).(2y+1)=7
=> (x-3).(2y+1)=1.7
Vậy nếu x-3=1 thì x=4; y=3
Nếu x-3=7 thì x=10;y=0
(x-3).(2y+1)=7
=>(x-3).(2y+1)=1.7
vậy nếu x-3=1 thì x=4; y=3
nếu x-3=7 thì x=10;y=10
tick nha
(x-3).(2y+1)=7
=> (x-3).(2y+1)=1.7
Vậy nếu x-3=1 thì x=4; y=3
Nếu x-3=7 thì x=10;y=0
(x-3).(2y+1)=7
=>(x-3).(2y+1)=1.7
vậy nếu x-3=1 thì x=4; y=3
nếu x-3=7 thì x=10;y=10
tick nha
Tìm số nguyên x;y biết
x.(y-1)=3
(x-3).(y-1)=2
(3x-2).(2y-3)=1
(2x-1).(2y-7)=5
Tim x biet
a)x(2y-1)-2y=-7
b)2|x|/3+|y|/2=5/3
( 2y +1 ) x 74 = 3 x 75
4 x 2 y + 1 - 3 = 125
15 - 2 x \y-3\ = -5
2y +5 chia hết y + 1
tim x :(x--3).(2y+1)=7
Tìm x,y biết :
1,(x-3)(y-1)=7
2,xy+3x-7y=21
3,xy+3x-2y=11
4,(x+1)(y-1)=-2
5,|x|=2x-6
6,|2y-4|<2
7,x(x+2)<0
8,x(x-y)=5
9,x(x-2)<0
10,(x+2)(3-x)>0
11,(x-2y)(y-1)=5
a)2x.(x-1)=0
b)x.(2x-4)=0
c)(x-3).(2y+1)=7
d)xy+3x-2y=11
(x-3).(2y+1)=7
(x - 3)(2y + 1) = 7
Tìm tất cả các số nguyên x,y sao cho:
a,xy=3
b,x(2y+3)=6
c,(x-1)(3-y)=-7
d,(x-2)(2y-1)=4
tìm x:
(x-3).(2y+1)=7