\(\left(x-\frac{3}{2}\right)^2=\frac{9}{16}\)
\(\Rightarrow\left(x-\frac{3}{2}\right)^2=\frac{3}{4}^2\) hoặc \(\left(x-\frac{3}{2}\right)^2=\left(-\frac{3}{4}\right)^2\)
\(\Rightarrow x-\frac{3}{2}=\frac{3}{4}\) hoặc \(x-\frac{3}{2}=-\frac{3}{4}\)
\(\Rightarrow x=\frac{9}{4}\) hoặc \(x=\frac{3}{4}\)
Ai thấy đúng thì ******** nha
(x-3/2)2=9/16
(x-3/2)2=(3/4)2
x-3/2=3/4
x =3/4+3/2
x =9/4
Có 2 trường hợp :
TH1: (x - 3/2)^2 = (3/4)^2
<=> x - 3/2 = 3/4
<=> x = 3/4 + 3/2
<=> x = ........Tự tính nhá!
TH2: (x - 3/2)^2 = (-3/4)^2
<=> x - 3/2 = -3/4
<=> x = -3/4 + 3/2
<=> x =..........Tự tính nhé!
Vậy có 2 giá trị là ..............
Có ( x - \(\frac{3}{2}\) )2 = \(\frac{9}{16}\)
( x - \(\frac{3}{2}\) )2 = \(\left(\frac{3}{4}\right)^2\)
\(\Rightarrow\) x - \(\frac{3}{2}=\frac{3}{4}\)
x \(=\frac{3}{4}+\frac{3}{2}\)
x \(=\frac{9}{4}\)
Ta có:(x-3/2)^2=9/16
=3/4.3/4
=3/4^2
Suy ra:x-3/2=3/4 hoac x-3/2=-3/4
x=3/4+3/2 x=-3/4+3/2
x=9/4 x=3/4