Question

(x-3)^2+ -9/25= 2/5.8/5

Answer 1

\(\left(x-3\right)^2+\frac{-9}{25}=\frac{2}{5}.\frac{8}{5}\)

\(\left(x-3\right)^2+\frac{-9}{25}=\frac{16}{25}\)

\(\left(x-3\right)^2=\frac{16}{25}+\frac{-9}{25}\)

\(\left(x-3\right)^2=\frac{7}{25}\)

\(\left(x-3\right)^2=\left(\frac{7}{5}\right)^2\)

\(\Rightarrow x-3=\frac{7}{5}\)

\(\Rightarrow x=\frac{7}{5}+3\)

\(\Rightarrow x=\frac{22}{5}\)

Answer 2

\(\left(x-3\right)^2+\left(\frac{-9}{25}\right)=\frac{2}{5}.\frac{8}{5}\)

\(\left(x-3\right)^2+\left(\frac{-9}{25}\right)=\frac{16}{25}\)

\(\left(x-3\right)^2=1=1^2\)

\(\Rightarrow x-3=1\)

\(\Rightarrow x=4\)

P/s: Hoq chắc :<

Answer 3

( x - 3 )²  + \(\frac{-9}{25}=\frac{2}{5}.\frac{8}{5}\)

 ( x - 3 )²  + \(\frac{-9}{25}=\frac{16}{25}\)

( x - 3 ) ²  = \(\frac{16}{25}-\frac{-9}{25}\)

( x - 3 )² = 1² = ( -1 )² 

\(\hept{\begin{cases}x-3=-1\\x-3=1\end{cases}}=>\hept{\begin{cases}x=2\\x=4\end{cases}}\)

vậy x = 2 , 4 

Answer 4

Não t :(( Bổ sung TH 2 nhé

\(\left(x-3\right)^2=1^2\)

\(\Rightarrow\orbr{\begin{cases}x-3=1\\x-3=-1\end{cases}\Rightarrow}\orbr{\begin{cases}x=4\\x=2\end{cases}}\)

P/s: 🌟_ Sao Thổ _🌟  Theo tớ thì nên dùng dấu \(\orbr{\begin{cases}\\\end{cases}}\)sẽ đúng hơn. Ý kiến riêng sai thông cảm :))

Answer 5

 Tớ ko biết sài sái kia !! Bỏ qua đi bạn Hoàng Thiên !! =.=