\(\left(x-3\right)^2+7=71\)
\(\left(x-3\right)^2\) \(=71-7\)
\(\left(x-3\right)^2\) \(=64\)
\(\left(x-3\right)^2\) \(=8^2\)
\(x-3\) \(=8\)
\(x=8+3\)
\(x=11\)
\(\left(x-3\right)^2=71-7.\)
\(\left(x-3\right)^2=64\)
\(\left(x-3\right)^2=8^2\)
\(x-3=8\Rightarrow x=8+3=11\)
<=> (x-3)^2 = 64 <=>\(\orbr{\begin{cases}x-3=8\\x-3=-8\end{cases}\Leftrightarrow\orbr{\begin{cases}x=11\\x=-5\end{cases}}}\)
vậy x thuộc {-5; 11}
(x-3)2=71-7=64
(x-3)2=82
x-3=8=>x=8+3=11
( x - 3 ) 2 = 71 - 7
( x - 3 ) 2 = 64
( x - 3 ) 2 = 82
=> x - 3 = 8
x = 8 + 3
x = 11
