Question

(x + 3)² + ( 4 + x)(4 – x) = 10

 

Answer 1

em moi l op 6 

Answer 2

\(\Leftrightarrow x^2+6x+9+16-x^2-10=0\)

\(\Leftrightarrow6x=-15\)

\(\Leftrightarrow x=-\frac{5}{2}\)

vậy.....

Answer 3

(x+3)^2+(4+x)(4-x)=10

=>(x+3)^2+16-x^2=10

=>[(x+3)^2-x^2]+16=10

=>(x+3-x)(x+3+x)=10-16=-6

=>3(2x+3)=-6

=>2x+3=-2

=>2x=-5<=>x=-5/2

Answer 4

\(x^2+6x+3^2+4^2-x^2=10\)0

\(6x+9+16=10\)

\(6x+25=10\)

\(x=\frac{-5}{2}\)

Answer 5

Kết bạn đi . Mik cx lớp 6

Answer 6

x²+2.x.3+3²+4²- x²

=x²+6x+9+16-x²

=6x+25=10

=6x     = 10-25

= 6x    = -15

=x      = -15/6=-5/2