\(\left(x-3\right)\left(10-2x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\10-2x=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\-2x=-10\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=5\end{matrix}\right.\)
a) 7x .(2x+10)=0
b)-9x:(2x-10)=0
c) (4-x) (x+3)=0
d) (x+2023) . (x - 2024)=0
Tìm xEZ, biết
a) 7x .(2x+10)=0
b)-9x:(2x-10)=0
c) (4-x) (x+3)=0
d) (x+2023) . (x - 2024)=0
Tìm số tự nhiên x biết:
a) (10-2x).(3x-18)=0 b) 10 + 2x = 165: 216 c) 28 - 2.(x - 4)2=10 d) (15-x)3.(x2 + 16) = 0 e) 52x - 3 - 2.52 = 52 . 3
f) (8 - x3).(x2 + 16) = 0 j) (2x + 5) + (2x + 10) +(2x + 15) +...+(2x + 95) = 77520
a, ( x + 5 ) ( 2x - 4 ) = 0
b, ( x - 3 ) ( 5x - 10 ) = 0
(x-3).(10-2x)=0
(x-3)*(10-2x)=0
Tìm x,y biết :
(x^2+2x)=0
x^3-4x=0
3x+4chia hết cho x+1
(2x+1).(y-3)= -10
x^2+2x=0
x^3-4x=0
3x+4x chia hết cho x+1
(2x+1).(y-3)= -10
