Question

x​​/2=y/3=z/5 và x*y*z=810 tìm x ,y ,z

 

Answer 1

đặt x/2 = y/3 = z/5 = k

=> x = 2k ; y = 3k ; z = 5k

vì xyz = 810

hay 2k . 3k . 5k = 810

30k³ = 810

k³ = 27

=> k = 3

Từ đó suy ra : a = 6 ; b = 9 ; z = 15

Vậy ...

Answer 2

Gọi \(\frac{x}{2}=\frac{y}{3}=\frac{z}{5}=k\)

\(\Rightarrow x=2k;y=3k;z=5k\)

\(\Rightarrow x.y.z=2k.3k.5k=810\)

\(\Rightarrow30k^3=810\)

\(\Rightarrow k^3=27\)

\(\Rightarrow k=3\)

\(\Rightarrow x=3.2=6\)

      \(y=3.3=9\)

      \(z=3.5=15\)

Vậy x = 6; y = 9; z = 15

Answer 3

ta có: x/2=y/3=z/5

x*y*z=810

=> x/2=y/3=z/5=x*y*z/2*3*5=810/30=27

x/2=27=> x=27*2=54

y/3=27=> y=27*3=81

z/5=27=> z=27*5=135

vậy x=54

y=81

z=135