\(x+2x+3x+....+9x=990.\)
\(\Rightarrow x.\left(1+2+3+....+9\right)=990\)
\(\Rightarrow x.45=990\)
\(\Rightarrow x=990:45\)
\(\Rightarrow x=22\)
X duoc xuat hien so lan la:
1+2+3+4+5+6+7+8+9=45
x=990÷45=22
ĐS:22
x + 2x + 3x + ... + 9x = 990
( 1 + 2+ 3 + ... + 9 ) . x = 990
45 . x = 990
x = 990 : 45
x = 22
Ta có: x + 2x + 3x +...+ 9x = 990
\(\Leftrightarrow\)(1 + 2 +3 +...+ 9)x = 990
\(\Leftrightarrow\)45x = 990
\(\Leftrightarrow\)x = 990/45 = 22
Vậy x = 22
x + 2x+3x+...+9x = 990
1x + 2x+3x+...+9x = 990
x .(1+2+3+...+9) = 990
Đặt A = 1 + 2 + 3 +...+9 (có 9 số hạng)
A= (1+9) . 9 : 2
A = 10. 9 : 2
A = 45
=> x . 45 = 990
x = 990 : 45
x = 22
Vậy x = 22