+) x-2=x
=> x-x=2
=> 0=2 (vô lí, loại)
+) x-2=-x
=> x+x=2
=> 2x=2
=> x=1
Vậy x=1.
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B1:tìm x biết a, (-2+x^2)(x^2-2)(x^2-2)(x^2-2)(x^2-2)=1 b, (2x+3)(x-4)+(x-5)(x-2)=(3x-5)(x-4) c,(8x-3)(3x+2)-(4x+7)(x+4)=(4x+1)(5x-1) d, 2x^2+3(x-1)(x+1)=5x(x+1) e, (8-5x)(x+2)+4(x-2)(x+1)=(2+x)(2-x) f, 4(x-1)(x+5)-(x+2)(x+5)=3(x-1)(x+2)
Bài 1:
a, (-2+x\(^2\))(x\(^2\)-2)(x\(^2\)-2)(x\(^2\)-2)(x\(^2\)-2)=1
b, (2x+3)(x-4)+(x-5)(x-2)=(3x-5)(x-4)
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e,(8-5x)(x+2)+4(x-2)(x+1)=(2+x)(2-x)
f, 4(x-1)(x+5)-(x+2)(x+5)=3(x-1)(x+2)
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Tính(x)+g(x)và f(x)-f(x)với:
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C(x)=x^2+2x
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E(x)=2x^2+3x
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H(x)=9x^3-4x
k(x)=x^3+x
Bài 1. Tìm x.a) -5(x2-3x+1)+x
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Đọc tiếp
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