ai trả lời tớ k
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(x-2)2=100
(x-2)2=102
=> x-2 =10
x =12
Vậy x=12
\(\text{(x-2)^2=100}\)
\(\Rightarrow x-2=\left(\pm10\right)\)
\(\orbr{\begin{cases}x-2=10\\x-2=-10\end{cases}\Leftrightarrow\orbr{\begin{cases}x=12\\x=-8\end{cases}}}\)
Vậy \(x\in\left(12;-8\right)\)
học tốt
\(\left(x-2\right)^2=100\)
\(\left(x-2\right)^2=10^2=\left(-10\right)^2\)
\(\Rightarrow x-2=10\)hoặc\(x-2=-10\)
\(x=12\)hoặc \(x=-8\)
Vậy \(x\in\left\{-8;12\right\}\)
