\(x-25-2\left(x+5\right)=0\)
\(x-25-2x-10=0\)
\(-x-35=0\)
\(-x=35\)
\(x=-35\)
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Phân tích thành nhân tử
(x-3)^2-5(x-2)+5=0
(2x-1)^2-3(x-2)(x+2)-25=0
2(x + 3) - x mũ 2 - 3x = 0
(3x - 5 ) mũ 2 - ( x -1) = 0
3x ( x - 5 ) - x mũ 2 +25 = 0
a)(x+2)-(x+1)^2=0
b)1-(x-2)^2=0
c)x+5-x^2+25=0
\(a,2x^2+8x=0\)
\(b,x^2-25+\left(x-5\right)^2=0\)
Tìm x
Tìm x
1. (3x+5)(4-3x)=0
2. 9(3x-2)=x(2-3x)
3. 25x^2 -2=0
4. x^2- 25=6x-9
5. (2x-1)^2-(2x+5)(2x-5)=18
6. x^3-8=(x-2)^3
7. x^3-4x^2+4x=0
8. x^2- 25+2(x+5)=0
9. 2(x^2+8x+16)- x^2+4=0
10. x^2(x-2)+7x=14
Tìm x biết a) 2x(x-5)-9(5-x)=0
b) (x+2)^2-25=0
1) x^2-25+2(x+5)=0
2) x(x-1)+x-1=0
3) (3x-2)^2-(x+2)^2=0
4) 2(x-2)-x^2+4x-4=0
5) 2(x^2+8x+16)-x^2+4=0
Tìm x biết: (x^2-25)^2-(x+5)^2=0
Tìm x
a, (5-x)+x^2-25=0
b, 2x^2+3x-5=0
c, (x^2-x)+4 (x^2-x) -12=0
d, (x-6)^4+ (x-8)^4=16