\(\left|x-2\right|=3\)
\(\Rightarrow x-2=\left\{3;-3\right\}\)
\(\hept{\begin{cases}x-2=3\\x-2=-3\end{cases}}\)
\(\hept{\begin{cases}x=2+3=5\\x=-3+2=-1\end{cases}}\)
\(\Rightarrow KL\)
|x - 2| = 3
x = 3 + 2
x = 5
hoặc x = -1
Vậy x = {5 , -1}
\(|x-2|=3\)
\(\Rightarrow x-2=3\)hoặc \(x-2=-3\)
Xét \(x-2=3\)\(x=3+2\)
\(x=5\)
Xét \(x-2=-3\)\(x=\left(-3\right)+2\)
\(x=-1\)
Vậy x = 5 hoặc x = -1