Ta có :
\(\frac{x-2}{27}=\frac{3}{x-2}\)
\(\Leftrightarrow\)\(\left(x-2\right)\left(x-2\right)=3.27\)
\(\Leftrightarrow\)\(\left(x-2\right)^2=81\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}x-2=\sqrt{81}\\x-2=-\sqrt{81}\end{cases}}\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}x-2=9\\x-2=-9\end{cases}}\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}x=11\\x=-7\end{cases}}\)
Vậy \(x=11\) hoặc \(x=-7\)
Chúc bạn học tốt ~
nhanh len nhe ai nhach minh k cho
* ta có: \(\frac{x-2}{27}\)\(=\frac{3}{x-2}\)
\(\Rightarrow\)\(\left(x-2\right)\left(x-2\right)\)\(=\)\(27.3\)
\(\Rightarrow\)\(\left(x-2\right)^2\)\(=81\)\(\)
\(\Rightarrow\)\(\left(x-2\right)^2\)\(=9^2\)hoặc \(\left(x-2\right)^2\)\(=\left(-9\right)^2\)'
\(\Rightarrow\)\(x-2\)= \(9\)hoặc \(x-2\)\(=-9\)
\(\Rightarrow\)\(x=\)\(7\)hoặc \(x=-7\)
Vậy x= 7 hoặc x= - 7
