Vì (x-1/5)2004 ≥ 0 ; (y+0.4)100 ≥ 0 ; (z-3)678 ≥ 0 với mọi x,y,z
Để (x-1/5)2004+(y+0.4)100+(z-3)678=0 <=> (x-1/5)2004 = 0 ; (y+0.4)100 = 0 ; (z-3)678 = 0
=> x-1/5 = 0 ; y+0.4=0 ; z-3=0
=> x=1/5 ; y=-0.4 ; z=3
(x-1/5)2004+(y+0.4)100+(z-3)678=0
(x-1/5)^2004 +(y 0.4)^100 +(z-3)^678
\(\left(x-\frac{1}{5}\right)^{2004}+\left(y+0.4\right)^{100}+\left(z-3\right)^{678}=0\)
\(\left(x-\frac{1}{5^{ }}\right)^{2004}+\left(y+0.4\right)^{100}+\left(z-3\right)^{678}=0\)
(x-1/5)mũ 2004+(y+0.4)mũ 100+(z-3)mũ 678=0 <sorry,viết ko rõ>iusp me với
( x - \(\frac{1}{5}\) ) ^2004+ ( y+0.4) ^ 100 + ( z-3 )^ 678 = 0
Giúp mình với !
tìm x, y, z khi:
a,cho 3x=y , 5y=4z và 6x+7y+8z = 456
b, \(\frac{4-z}{1}=\frac{y+z}{2}=\frac{x+y}{3}=\frac{y+8}{5}\)
c, ( x - \(\frac{1}{5}\)) ^2004+ ( y+0.4) ^ 100 + ( z-3 )^ 678 = 0
Tìm ba số x, y , z biết rằng:
(x - 1/5)2004 + (y + 0,4)100 + (z - 3)678 = 0
(x – 1/5)^2004 + (y + 0,4)^100 + (z – 3)^678 = 0
