(x - 1)5 = -32
=> (x - 1)5 = (-2)5
=> x - 1 = -2
=> x = -2 + 1
=> x = -1
Vậy ...
\(\left(x-1\right)^5=-32\)
\(\Rightarrow\left(x-1\right)^5=-2^5\)
\(\Rightarrow x-1=-2\)
\(\Rightarrow x=-2+1=-1\)
Vậy x = -1
\(\left(\times-1\right)^5=-32\)
\(\left(\times-1\right)^5=\left(-2\right)^5\)
\(\times-1=-2\)
\(\times=-1\)
Xin chân thành cảm ơn các cậu đã giúp mình nha. :>>
ko ghi lại đề
(x-1)5=(-2)5
x-1=-2
x=-2+1
x=-1
@๖ۣۜAƙαĭ ๖ۣۜHαɾυмα•™ [ RBL ] ❧Bacon☙: \(\left(-2\right)^5=32\) nhé thg óc :)))
ko ghi lại đề
(x-1)5=-25
=>x-1=-2
x=-2+1
=-1
\(\left(x-1\right)^5=-32\)
\(\Rightarrow\left(x-1\right)^5=\left(-2\right)^5\)
\(\Rightarrow x-1=-2\)
\(x=-2+1\)
\(x=-1\)
Vậy x = -1
\(\left(x-1\right)^5=-32\)
\(\Rightarrow\left(x-1\right)^5=\left(-2\right)^5\)
\(\Rightarrow x-1=-2\)
\(\Rightarrow x=-2+1\)
\(\Rightarrow x=-1\)
( x - 1 )5 = -32
( x - 1 )5 = ( -2 )5
x - 1 = -2
x = -2 - 1
x = -1
Vậy x = -1
~ Hok tốt ~
( x-1)^5= -32
=>( x - 1)5 = -25
=> x - 1 = -2
=> x = -2+1
=> x = -1
Vậy .....