\(\left(x-1\right)^3=\left(x-1\right)^4\)
\(\Rightarrow\left(x-1\right)^3-\left(x-1\right)^4=0\)
\(\left(x-1\right)^3\left(1-x+1\right)=0\)
\(\left(x-1\right)^3\left(2-x\right)=0\)
Khi \(x-1=0\) Hoặc \(2-x=0\)
TH1 \(x-1=0\Rightarrow x=1\)
TH2 \(2-x=0\Rightarrow x=2\)
Vậy x=1 hoặc x=2
\(\left(x-1\right)^3=\left(x-1\right)^4=>\left(x-1\right)^3-\left(x-1\right)^4=0=>\left(x-1\right)^3.\left[1-\left(x-1\right)\right]=0\)
=>(x-1)^3=0
hoặc 1-(x-1)=0
=>x=1
hoặc x-1=1=>x=2
vậy x=1;x=2
liike nhé