\(\Leftrightarrow x^2-2x+1-x^3-9x^2-27x-27=8\\ \Leftrightarrow-x^3-8x^2-29x-34=0\\ \Leftrightarrow x^3+8x^2+29x+34=0\\ \Leftrightarrow x^3+2x^2+6x+12x^2+17x+34=0\\ \Leftrightarrow\left(x+2\right)\left(x^2+6x+17\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=-2\\\left(x+3\right)^2+8=0\left(vô.n_o\right)\end{matrix}\right.\Leftrightarrow x=-2\)
13-(3.x^2+5x-8).(2x-1)=(-2.x^2-3.x+1).(x+3/8).6.x
Tính các biểu thức
3 x (22 + 1) x (24 + 1) x (28 + 1) x...x (264 + 1) + 1
8 x (32 + 1) x (34 + 1) x (38 + 1) x...x (3128 + 1) + 1
12 x (52 + 1) x (54 + 1) x (58 + 1) x (516 + 1)
I) phan tich
1, 3x^2 - 11x+6
2, 8x^2 + 10x-3
3, 9x^2-9xy-xy
4, x^3+x+2
5, x^8y^8+x^4y^4 + 1
6, x^5+x^4+1
7, x^8+x^2+1
8, x^8+x+1
tính gt biểu thức
a)P=(x^3+6x^2+12x+8)+3(x^2+4x+4)y+3(x+2)y^2+y^3 với x+y=8
b)Q=(x-1)^3-4x(x+1)(x-1)+3(x-1)(x^2+x+1) với x=-2
(x+1)(x-1)+(x+2)(x-2)+(x+3)(x-3)+(x+4)(x-4)+(x+5)(x-5)+(x+6)(x-6)+(x+7)(x-7)+(x+8)(x-8)=?
Rút gọn 1) (x-2)^2 - (x+1) (x-1)
2)(3x-2) (3x+2)-(3x+1)^2
3)(x-8) (x+8)-(x+3)^2
4) (2x+y)^2 -2(4x^2-y^2)+(2x-y)^2
Bài 2 tìm x
a) (x+3)^2 - (x-2) (x+2)=8
b) (x-5)^2 - 9 =0
Bài 3 so sánh
A=(2+1) (2^2+1) (2^4+1) (2^8+1) và B = 2^16 .
a, 1/x-1 + 2/x^2+x+1 = 3x^2/x^2-1
c, x/2(x-3) + x/2(x+1 ) = 2x/(x+1 )(x-3)
b, 8-x/x-7 - 8 = 1/1-7
(x+1)(x^2-x+1) - x(x-3)(x+3)=8
Tìm x
a) 4(x + 1)2 + (2x + 1)2 - 8(x – 1)(x + 1) - 11=0
b)(x + 3)2 – (x – 4)(x + 8) – 1 = 0
\(\frac{x+4}{x-1}+\frac{x-4}{x+1}=\frac{x-8}{x+2}+\frac{x+8}{x-2}-\frac{8}{3}\)
