( x - \(\frac{1}{2}\) ) - \(\frac{3}{4}\) = 0
x - \(\frac{1}{2}\) = 0 + \(\frac{3}{4}\)
x - \(\frac{1}{2}\) = \(\frac{3}{4}\)
x = \(\frac{3}{4}\) + \(\frac{1}{2}\)
x = \(\frac{3}{4}\) + \(\frac{2}{4}\)
x = \(\frac{5}{4}\)
~ Hok T ~
I\(x-\frac{1}{2}\)I\(-\frac{3}{4}=0\)
I\(x-\frac{1}{2}\)I\(=0+\frac{3}{4}\)
I\(x-\frac{1}{2}\)I= \(\frac{3}{4}\)
Ta có 2 trường hợp :
TH1 :
\(x-\frac{1}{2}=\frac{3}{4}\)
\(x=\frac{3}{4}+\frac{1}{2}\)
\(x=\frac{5}{4}\)
TH2:
\(x-\frac{1}{2}=-\frac{3}{4}\)
\(x=(-\frac{3}{4}) + \frac{1}{2}\)
\(x=-\frac{1}{4}\)
Vậy x = \(\frac{5}{4}\) hoặc\(-\frac{1}{4}\)
|x - 1/2| - 3/4= 0
|x - 1/2| = 3/4
x - 1/2 = 3/4 hoặc x - 1/2 = - 3/4
x = 3/4 + 1/2 hoặc x = - 3/4 + 1/2
x = 5/4 hoặc x = - 1/4
Vậy x = 5/4; x = - 1/4