Ta có: (x+1)+(x+2)+....+(x+100) = 5750
=> (x+x+x+...+x) + (1+2+3+3+.....+100) = 5750
=> 100x + 5050 = 5750
=> 100x = 5750 - 5050 = 700
=> x = 700:100
=> x = 7
Vậy x = 7
(x+1)+(x+2)+(x+3)+...+(x+100)=5750
x + 1 + x + 2 + x + 3 + .... + x + 100 = 5750
(x + x + x + ... + x) + (1 + 2 + 3 + ... + 100) = 5750
100x + 5050 = 5750
100x = 5750 - 5050 = 700
x = 700 : 100 = 7
( x + 1) + ( x + 2) + ... + (x + 100) = 5750
(x + x + x + ... + x ) + (1 + 2 + ... + 100) = 5750
100x + (1 + 2 + ... + 100) = 5750
100x + 5050 = 5750
100x = 5750 - 5050
100x = 700
x = 7
[x+1] + [x+2] + [x+3] + ........+ [x+100] = 5750
<=>100x +(1+2+3+4+....+100)=5750
<=>100x + (1+100)x50 =5750
<=> 100x + 101x50=5750
<=>100x+5050 = 5750
=>100x= 5750 - 5050
=>100x= 700
=>x=700:100
=>x=7
Bài viết tham gia Hoa điểm 10 2016(x+1) + (x+2) + (x+3) + ......+ (x+100) = 5750
<=> x+1+x+2+.............+x+100=5750
<=> 100x + (1+2+.......+100) =5750
<=> \(100x+\frac{\left(1+100\right).100}{2}=5750\)
<=> 100x + 5050 = 5750
<=> 100x = 5750 - 5050 = 700
<=> x = 700 : 100 = 7