( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ... + ( x + 100 ) = 5050
100x + 101.100 : 2 = 5050
100x + 5050 = 5050
100x = 0
x = 0
(x + 1) + (x + 2) + (x + 3) + ... + (x + 100) = 5050
(x + x + x + ... + x) + (1 + 2 + 3 + ... + 100) = 5050
100 số x
100.x + (1 + 100).100:2 = 5050
100.x + 101.50 = 5050
100.x + 5050 = 5050
=> 100.x = 0
=> x = 0
Ủng hộ mk nha ^_-
\(\text{( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ... + ( x + 100 ) = 5050 }\)
\(x+\left(100+1\right)\cdot100:2=5050\)
\(x+5050=5050\)
\(\Rightarrow x=0\)
Ta có:( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ... + ( x + 100 ) = 5050
<=> (x + x + x + .....+ x) + ...... + (1 + 2 + 3 + ..... + 100) = 5050
<=> 100x + 5050 = 5050
=> 100x = 0
=> x = 0
\(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+.....+\left(x+100\right)=5050\)
\(=100x\left(1+100\right).100:2=5050\)
\(=100x+101.50=5050\)
\(\Rightarrow100x=0\)
\(\Rightarrow x=0\)
( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ... + ( x + 100 ) = 5050
( x + x + x + ... + x ) + ( 1 + 2 + 3 + ... + 100 ) = 5050
x + ( 100 + 1 ) x 100 : 2 = 5050
x + 101 x 100 : 2 = 5050
x + 5050 = 5050
x = 5050 - 5050
=> x = 0
Vậy x = 0
Ta có:( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ... + ( x + 100 ) = 5050
<=> (x + x + x + .....+ x) + ...... + (1 + 2 + 3 + ..... + 100) = 5050
<=> 100x + 5050 = 5050
=> 100x = 0
=> x = 0