\(\left(x+1\right).\left(x+2\right).\left(x+3\right).....\left(x+10\right)=625\)
\(\Rightarrow\left(x+x+x+...+x\right).\left(1+2+3+...+10\right)=625\)
\(\Rightarrow10x.55=625\)
\(\Rightarrow10x=625:55\)
\(\Rightarrow10x=\frac{125}{11}\)
\(\Rightarrow x=\frac{125}{11}:10\)
\(\Rightarrow x=\frac{25}{22}\)
Học tốt #
\(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+10\right)=625\)
\(\left(x+x+x+...+x\right)+\left(1+2+3+...+10\right)=625\)
\(10x+\frac{\left(10+1\right)\cdot10}{2}=625\)
\(10x+55=625\)
\(10x=625-55\)
\(10x=570\)
\(x=570:10\)
\(x=57\)
Vậy \(x=57\)
Chúc bạn học tốt !!!
