Question

(x-1) . (x-2) = 2

giải bài này hộ mik với cảm ơn

Answer 1

\(x\left(x-2\right)-1\left(x-2\right)=2\)

\(x^2-2x-x+2-2=0\)

\(x^2-3x=0\)

\(x\left(x-3\right)=0\)

\(Th1:x=0\)

\(Th2:x-3=0=>x=3\)

Vậy\(x\in\left\{0;3\right\}\)

Toán 8 mà

Answer 2

(x-1).(x-2)=2

x²-2x-x+2=2

x²-3x=0

x(x-3)=0

TH1: x=0

TH2: x-3=0 =>x=3

Answer 3

x(x - 2) - 1(x-2) = 2

x^{2 -} 2x - x + 2 - 2 = 0

x² - 3x = 0

x(x-3) = 0

$\rightarrow$ x $\in$ {0; 3}