\(=>\left[{}\begin{matrix}x-0,25=1,75\\x-0,25=-1,75\end{matrix}\right.=>\left[{}\begin{matrix}x=1,75+0,25\\x=-1,75+0,25\end{matrix}\right.=>\left[{}\begin{matrix}x=2\\x=-1,5\end{matrix}\right.\)
\(\left|x-0,25\right|=1,75\)
TH1: \(x-0,25=1,75\Rightarrow x=1,75+0,25\Rightarrow x=2\)
TH2: \(x-0,25=-1,75\Rightarrow x=-1,75+0,25\Rightarrow x=-1,5\)
\(\left|x-0,25\right|=1,75\)
\(\Rightarrow\left\{{}\begin{matrix}x-0,25=1,75\\x=1,75+0,25\\x=2\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x-0,25=-1,75\\x=-1,75+0,25\\x=-1,5\end{matrix}\right.\)
Vậy \(x\in\left\{2;-1,5\right\}\)