`@` `\text {Ans}`
`\downarrow`
`x \div 0,2 + x \div 0,5 - x \times 2 = 12,03`
`x \div 2/10 + x \div 5/10 - x \times 2 = 12,03`
`x \times 10/2 + x \times 10/5 - x \times 2 = 12,03`
`x \times 5 + x \times 2 - x \times 2 = 12,03`
`x \times ( 5+2-2) = 12,03`
`x \times 5 = 12,03`
`x = 12,03 \div 5`
`x =2,406`
Vậy, `x = 2,406.`