Ta thay x = 2
\(g\left(2\right)=\frac{2^2-2\times2+5}{2-1}\)
\(g\left(2\right)=\frac{4-2\times2+5}{1}\)
\(g\left(2\right)==\frac{4-4+5}{1}\)
\(g\left(2\right)=\frac{5}{1}\)
\(g\left(2\right)=5\)
Vậy g(2) = 5
Vói \(g\left(x\right)=\frac{x^2-2x+5}{x-1}\)
Thay : g(2) \(=\frac{2^2-2.2+5}{2-1}\)
\(=\frac{4-4+5}{2-1}\)
\(=\frac{5}{1}\)
\(=5\)
Vậy : khi thay g(2) vào \(\frac{x^2-2.x+5}{x-1}\) thì sẽ bằng 5